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Answer: First, let's draw a picture of the situation.If 4 amps of current is flowing through the 3-ohm resistor, then 4 amps of current must be flowing through the 6-ohm resistor according to Kirchhoff's Current Law.
Kirchhoff's Current Law (KCL), named after German physicist Gustav Kirchhoff, states that the sum of all current entering any point in a circuit has to equal the sum of all current leaving any point in a circuit.
More simply, this is another way of looking at the law of conservation of charge.
Now you can analyze your equivalent series circuit with a VIRP table.
Once your table is complete, work back to your original circuit using KCL and KVL until you know the current, voltage, and resistance of each individual element in your circuit.
For example if our voltage was 4 Volts and our total resistance was 9 Ohm’s, then our current (I) would be 4/9 Amps, which is equal to 0.4444 Amps.
The circuit is connected to an AC voltage source with amplitude 25 V and frequency 50 Hz.At Table 1 you can find tips for calculating the math values required in this instructable. Look at the circuit you are given and identify which type of resistance your circuit uses, then you may proceed to step 2.The voltage of a circuit is displayed by the symbol found in Fig. You can simply transcribe this value and keep it until we are solving for current (I) in Step 3. These resistors can be organized in two basic ways, either in parallel or in series. Series resistors look like a “string” on a circuit, each one is placed end-to-end in a row, all traveling in the same direction. Because Ohm’s Law is found to be “I=V/R”, then we need one single, total value for resistance (R).For example, we know the total voltage in the circuit (12V) provided by the battery, and we know the values for resistance for each of the individual resistors: If I look at the bottom (total) row of my table, I know both the voltage drop (V) and the resistance (R).Knowing these two items, I can calculate the total current flow in the circuit using Ohm's Law, and I can also calculate the total power dissipated in the circuit using my formulas for electrical power: So what does this table really tell us now that it's completely filled out?Determine the amplitude of electric current in the circuit and a phase difference between the voltage and the current. The table of contents will list only tasks having one of the required ranks in corresponding rankings and at least one of the required tags (overall).If you wish to filter only according to some rankings or tags, leave the other groups empty.We know the potential drop across each resistor (4V), the current through each resistor (2 m A), and the power dissipated by each resistor (8 m W).In addition, we know the total potential drop for the entire circuit is 12V, and the entire circuit dissipated 24 m W of power.First, look for portions of the circuit that have parallel elements.Since the voltage across the parallel elements must be the same, replace the parallel resistors with an equivalent single resistor in series and draw a new schematic.